-
Bug
-
Resolution: Not A Defect
-
Minor
-
None
-
Jenkins 1.651.2
I am using groovy scripts copied to /usr/share/jenkins/ref/init.groovy.d/ to do the initial setup of a Docker Jenkins instance. Later I create jobs using the Job DSL Plugin that require Xvfb.
I can't figure out how to initialize a "default" installation of Xvfb using groovy scripts. I have a work-around where I put a copy of org.jenkinssci.plugins.xvfb.XvfbBuildWrapper.xml and then in the groovy scripts I have one script that runs "Jenkins.instance.doReload()". This broke when I upgraded from 1.0.6 to 1.1.3 since the format of the xml file changed.
What is the right way to script the creation of a default Xvfb installation?
[JENKINS-34809] How to set default xvfb installation?
zregvart
added a comment - Hi Chris, I've answered on stackoverflow, pasted here for others to find as well:
Use this script in `init.groovy.d` directory:
import jenkins.model.Jenkins import org.jenkinsci.plugins.xvfb.* def installation = new XvfbInstallation('default', '/usr/local/bin', null) Jenkins.getInstance() .getDescriptorByType(Xvfb.XvfbBuildWrapperDescriptor.class) .setInstallations(installation)
The `default` is the name of the Xvfb installation, and `/usr/local/bin` is the directory where Xvfb binary resides, change accordingly.
zregvart
added a comment - Hi Chris, I've answered on stackoverflow, pasted here for others to find as well:
Use this script in `init.groovy.d` directory:
import jenkins.model.Jenkins
import org.jenkinsci.plugins.xvfb.*
def installation = new XvfbInstallation( ' default ' , '/usr/local/bin' , null )
Jenkins.getInstance()
.getDescriptorByType(Xvfb.XvfbBuildWrapperDescriptor.class)
.setInstallations(installation)
The `default` is the name of the Xvfb installation, and `/usr/local/bin` is the directory where Xvfb binary resides, change accordingly. 
Chris Hubbard
added a comment - This worked. Thanks! 
Should this be an issue for DSL Plugin or xvfb Plugin?